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	<title>Comments on: I like Miso Soup</title>
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	<link>http://www.pcpro.co.uk/blogs/2008/07/29/i-like-miso-soup/</link>
	<description>Blogging in the real world</description>
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		<title>By: server rack cooling</title>
		<link>http://www.pcpro.co.uk/blogs/2008/07/29/i-like-miso-soup/comment-page-1/#comment-10743</link>
		<dc:creator>server rack cooling</dc:creator>
		<pubDate>Mon, 13 Oct 2008 02:33:37 +0000</pubDate>
		<guid isPermaLink="false">http://www.pcpro.co.uk/blogs/?p=2640#comment-10743</guid>
		<description>&lt;strong&gt;server rack cooling...&lt;/strong&gt;

I never thought I will agree with this opinion, but you know... I agree partially now...</description>
		<content:encoded><![CDATA[<p><strong>server rack cooling&#8230;</strong></p>
<p>I never thought I will agree with this opinion, but you know&#8230; I agree partially now&#8230;</p>
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		<title>By: Steve Cassidy</title>
		<link>http://www.pcpro.co.uk/blogs/2008/07/29/i-like-miso-soup/comment-page-1/#comment-4473</link>
		<dc:creator>Steve Cassidy</dc:creator>
		<pubDate>Thu, 31 Jul 2008 12:46:56 +0000</pubDate>
		<guid isPermaLink="false">http://www.pcpro.co.uk/blogs/?p=2640#comment-4473</guid>
		<description>You don&#039;t need to start from a balloon to get figures for server rooms, though it is a forest of incompatible units fed into simple bits of maths: a room of a given volume will contain a fairly well understood quantity (=weight) of air. The gap in appreciation comes in when dealing with the kilowatts of power pulled by a server rack, versus the usual rating of an aircon unit. Aircon people deal in BTU&#039;s -  which handily hides how much power they suck in on their own account. My guess (without having to calculate how many moles per kilofortnight are sucked up the elephant&#039;s trunk air exhaust) is that a portable aircon unit sized hopefullly to cook 1.25kW of servers is itself drawing (and dissipating) a further 3-5kW - and a painful amount of that dissipation is back into the room, from the surface of the &quot;trunk&quot; (=air exhaust).

However, I can read the mood of the day and I&#039;ll place a small side bet this turns into  a long thread about weighing hot air ballons with a periodic table, a slide rule, and a pyrometer...</description>
		<content:encoded><![CDATA[<p>You don&#8217;t need to start from a balloon to get figures for server rooms, though it is a forest of incompatible units fed into simple bits of maths: a room of a given volume will contain a fairly well understood quantity (=weight) of air. The gap in appreciation comes in when dealing with the kilowatts of power pulled by a server rack, versus the usual rating of an aircon unit. Aircon people deal in BTU&#8217;s &#8211;  which handily hides how much power they suck in on their own account. My guess (without having to calculate how many moles per kilofortnight are sucked up the elephant&#8217;s trunk air exhaust) is that a portable aircon unit sized hopefullly to cook 1.25kW of servers is itself drawing (and dissipating) a further 3-5kW &#8211; and a painful amount of that dissipation is back into the room, from the surface of the &#8220;trunk&#8221; (=air exhaust).</p>
<p>However, I can read the mood of the day and I&#8217;ll place a small side bet this turns into  a long thread about weighing hot air ballons with a periodic table, a slide rule, and a pyrometer&#8230;</p>
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	<item>
		<title>By: Drab</title>
		<link>http://www.pcpro.co.uk/blogs/2008/07/29/i-like-miso-soup/comment-page-1/#comment-4404</link>
		<dc:creator>Drab</dc:creator>
		<pubDate>Thu, 31 Jul 2008 08:02:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.pcpro.co.uk/blogs/?p=2640#comment-4404</guid>
		<description>Steve

I agree wholeheartedly with your comments on Grimer&#039;s behaviour - he was definitely looking for a fight. However you do not comment on his mathematics, I suppose I could go online and check it out for myself but it would be nice to know whether you accept his basic calculation re weight of air inside a balloon and hence the wieght of air inside an average server room, which would lead us nicely into reasonable recommendations for server room cooling.

Cheers

DRAB</description>
		<content:encoded><![CDATA[<p>Steve</p>
<p>I agree wholeheartedly with your comments on Grimer&#8217;s behaviour &#8211; he was definitely looking for a fight. However you do not comment on his mathematics, I suppose I could go online and check it out for myself but it would be nice to know whether you accept his basic calculation re weight of air inside a balloon and hence the wieght of air inside an average server room, which would lead us nicely into reasonable recommendations for server room cooling.</p>
<p>Cheers</p>
<p>DRAB</p>
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	<item>
		<title>By: Steve Cassidy</title>
		<link>http://www.pcpro.co.uk/blogs/2008/07/29/i-like-miso-soup/comment-page-1/#comment-4380</link>
		<dc:creator>Steve Cassidy</dc:creator>
		<pubDate>Wed, 30 Jul 2008 23:18:35 +0000</pubDate>
		<guid isPermaLink="false">http://www.pcpro.co.uk/blogs/?p=2640#comment-4380</guid>
		<description>Charmed, I&#039;m sure. Though in order to critique like that you need to show where I associate convection with balloons (I don&#039;t: the convection is in the soup, which you carefully ignore, like all good critics with a chip on their shoulders). As for the five ton figure,  it was told to me while I was standing in a balloon with a qualified balloon pilot who, since his job includes not crashing into the ground, I&#039;m prepared to listen to.

It sounds to me like you desperately need to be bad-tempered and misinterpretative for the sake of it, and need to find some way to vent your own hot air. Which is rather were I came in...</description>
		<content:encoded><![CDATA[<p>Charmed, I&#8217;m sure. Though in order to critique like that you need to show where I associate convection with balloons (I don&#8217;t: the convection is in the soup, which you carefully ignore, like all good critics with a chip on their shoulders). As for the five ton figure,  it was told to me while I was standing in a balloon with a qualified balloon pilot who, since his job includes not crashing into the ground, I&#8217;m prepared to listen to.</p>
<p>It sounds to me like you desperately need to be bad-tempered and misinterpretative for the sake of it, and need to find some way to vent your own hot air. Which is rather were I came in&#8230;</p>
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		<title>By: Grimer</title>
		<link>http://www.pcpro.co.uk/blogs/2008/07/29/i-like-miso-soup/comment-page-1/#comment-4353</link>
		<dc:creator>Grimer</dc:creator>
		<pubDate>Wed, 30 Jul 2008 19:25:06 +0000</pubDate>
		<guid isPermaLink="false">http://www.pcpro.co.uk/blogs/?p=2640#comment-4353</guid>
		<description>I just calculated the weight of the air in a balloon and came up with a rather different answer: 

Small one man balloon = 595 cubic metres = 595,000 litres
1 mol of air (at room temp) = 22.4 litres
80% Nitrogen + 20% Oxygen = (0.8x15x2) + (0.2x16x2) = 30.4g per mol

Therefore 595,000 litres = 26,562.5 mol = 807,500 grams = 0.8075 tonnes

However, hot air has less density than cold air (PV/T=K)

0.9486 kg/m³ for dry air heated to 210 °F (99 °C)

This would mean that 595 cubic metres of hot air = 0.564 tonnes

An average balloon has a capacity of 2,832 m³. If we scale up the previous answer: 

2832/595 = 4.75
4.75 x 0.564 tonnes = 2.68 tonnes 

Anyway, it isn&#039;t convection that keeps a balloon in the air. It is due to the difference in the density of the atmospheric air and the air trapped inside the balloon. This is a difference of over 30%. 

Hot air balloons rise for exactly the same reason that &#039;blimps&#039; rise. They are full of a low density gas. It has nothing to do with convection (although you could argue that convection is the phenomenon of a lower density gas rising up through a higher density gas).

It sounds like you&#039;re very lucky to get paid and don&#039;t really know what you&#039;re talking about. 

Sorry...</description>
		<content:encoded><![CDATA[<p>I just calculated the weight of the air in a balloon and came up with a rather different answer: </p>
<p>Small one man balloon = 595 cubic metres = 595,000 litres<br />
1 mol of air (at room temp) = 22.4 litres<br />
80% Nitrogen + 20% Oxygen = (0.8&#215;15x2) + (0.2&#215;16x2) = 30.4g per mol</p>
<p>Therefore 595,000 litres = 26,562.5 mol = 807,500 grams = 0.8075 tonnes</p>
<p>However, hot air has less density than cold air (PV/T=K)</p>
<p>0.9486 kg/m³ for dry air heated to 210 °F (99 °C)</p>
<p>This would mean that 595 cubic metres of hot air = 0.564 tonnes</p>
<p>An average balloon has a capacity of 2,832 m³. If we scale up the previous answer: </p>
<p>2832/595 = 4.75<br />
4.75 x 0.564 tonnes = 2.68 tonnes </p>
<p>Anyway, it isn&#8217;t convection that keeps a balloon in the air. It is due to the difference in the density of the atmospheric air and the air trapped inside the balloon. This is a difference of over 30%. </p>
<p>Hot air balloons rise for exactly the same reason that &#8216;blimps&#8217; rise. They are full of a low density gas. It has nothing to do with convection (although you could argue that convection is the phenomenon of a lower density gas rising up through a higher density gas).</p>
<p>It sounds like you&#8217;re very lucky to get paid and don&#8217;t really know what you&#8217;re talking about. </p>
<p>Sorry&#8230;</p>
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